Convert Celsius to Rankine
Unit definitions
Celsius
Celsius is defined by the temperatures at which water freezes ($0 \ \text{°C}$) and boils ($100 \ \text{°C}$) at standard atmospheric pressure. Temperature in Celsius is equal to $\text{K} - 273.15$.
Rankine
Rankine is a scale used in engineering systems in the United States. Temperature in $^{\circ}\text{R}$ is equal to $\text{K} \times \frac{9}{5}$.
How to convert Celsius to Rankine
$$\text{Temperature}_{\text{°R}} = \left( \text{Temperature}_{\text{°C}} + 273.15\right) \cdot \frac{9}{5}$$
Examples
Example 1
Convert $50.0\ \text{°C}$ to $\text{°R}$.
$$\text{Temperature}_{\text{°R}} = \left( 50.0 + 273.15\right) \cdot \frac{9}{5}$$
$$\text{Temperature}_{\text{°R}} = 581.67$$
$$\therefore \ 50.0\ \text{°C} = 581.67 \ \text{°R}$$
Example 2
Convert $80.0\ \text{°C}$ to $\text{°R}$.
$$\text{Temperature}_{\text{°R}} = \left( 80.0 + 273.15\right) \cdot \frac{9}{5}$$
$$\text{Temperature}_{\text{°R}} = 635.67$$
$$\therefore \ 80.0\ \text{°C} = 635.67 \ \text{°R}$$
Example 3
Convert $100.0\ \text{°C}$ to $\text{°R}$.
$$\text{Temperature}_{\text{°R}} = \left( 100.0 + 273.15\right) \cdot \frac{9}{5}$$
$$\text{Temperature}_{\text{°R}} = 671.67$$
$$\therefore \ 100.0\ \text{°C} = 671.67 \ \text{°R}$$
Example 4
Convert $145.0\ \text{°C}$ to $\text{°R}$.
$$\text{Temperature}_{\text{°R}} = \left( 145.0 + 273.15\right) \cdot \frac{9}{5}$$
$$\text{Temperature}_{\text{°R}} = 752.67$$
$$\therefore \ 145.0\ \text{°C} = 752.67 \ \text{°R}$$
Example 5
Convert $170.0\ \text{°C}$ to $\text{°R}$.
$$\text{Temperature}_{\text{°R}} = \left( 170.0 + 273.15\right) \cdot \frac{9}{5}$$
$$\text{Temperature}_{\text{°R}} = 797.67$$
$$\therefore \ 170.0\ \text{°C} = 797.67 \ \text{°R}$$
Celsius to Rankine conversion table
Convert Celsius to other Temperature units
| Celsius [°C] | Other unit |
|---|---|
| 1 | 274.15 Kelvin [K] |
| 1 | 33.8 Fahrenheit [°F] |